What is the volume of 5.60 g of o2 at 7.78 atm and 415k?
Answer:
0.765 dm³
Explanation:
Applying genera gas equation,
PV = nRT……………. Equation 1
Where P = pressure of the oxygen gas, V = Volume of the oxygen gas, n = number of mole of oxygen gas, T = Temperature of oxygen gas, R = Molar gas constant.
Make V the subject of the equation
V = nRT/P……………… Equation 2
But,
n = mass/molar mass
n = 5.6/(16×2)
n = 5.6/32
n = 0.175 moles.
Given: T = 415 K, P = 7.78 atm, n = 0.175 moles
Constant: R = 0.082 atm.dm³/K.mol
Substitute into equation 2
V = 0.175(0.082)(415)/7.78
V = 5.95525/7.78
V = 0.765 dm³