what is the volume occupied by 0.255 mol of helium gas at 1.25 atm and 305 k?

By Allen Kazadi

What is the volume occupied by 0.255 mol of helium gas at 1.31 atm and 301 K?

Answer:

Solution 59P

n = 0.255 mol of He

P = 1.25 atm

T = 305 K.

V= ?

This can be found using ideal gas equation :

PV = nRT

V =

We know, gas constant (R) = 0.0821 L.atm mol-1 K-1.

= 5.10 L.

Hence, volume of He is 5.10 L

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