**What is the standard form equation of the line shown below? Graph of a line going through negative 1, 5 and 2, 4**

**Answer:**

y = -1/3x + 14/3

**Step-by-step explanation:**

We have the standard equation as;

y = mx + b

where m is the slope and b is the y-intercept

the given points are;

(-1,5) and (2,4)

So we plug x and y for each of the points

then we create two linear equations which we can solve simultaneously to get the values of m and b

From the points;

5 = -m + b•••••••(i)

4 = 2m + b

from i;

b = 5 + m

substitute this into equation ii

4 = 2m + 5 + m

4 = 3m + 5

4-5 = 3m

3m = -1

m = -1/3

Recall;

b = 5 + m

b = 5-1/3

b = 14/3

so we have the equation as;

y = -1/3x + 14/3

Multiply through by 3

3y = -x + 14