What is the magnitude of the electric force on charge A in (Figure 1)?
magnitude of the electric force on charge A in (Figure 1)?” src=”https://img.breldigital.com/uploads/2022/04/03103757/What-is-the-magnitude.png” alt=”What is the magnitude of the electric force on charge A in (Figure 1)?” width=”429″ height=”261″ />
Answer:
Note that by Coulomb’s Law,
F = kq1q2/r^2
where
k = 8.99E9 Nm^2/kg^2 q1, q2 = the two interacting charges r = the distance of separation of the two charges
Thus, for force of B on A points to the right, as opposite charges attract. qA = 1.0E-9 C qB = -1.0E-9 C r = 0.01 m
Thus,
F(B on A) = 8.99E-5 N
Now, for force of C on A points to the left, as like charges repel.
Thus, as
qA = 1.0E-9 C qC = 4.0E-9 C r = 0.02 m
F(C on A) = -8.99E-5 N [the negative sign because it is to the left]
Thus,
Fnet (A) = F(B on A) + F(C on A)
Fnet (A) = 0.00 N
What is the magnitude of the electric force on charge A in (Figure 1)?
Read more: Your answer either contains an incorrect numerical multiplier or is missing one.