Solution
(a) In carbonate ion, the carbon atom is sp
2
hybridized and forms pi bond.
(b) In diamond, carbon atom is sp
3
hybridized and has tetrahedral geometry.
(c) In graphite, carbon atom is sp
2
hybridized.
Solution
(a) In carbonate ion, the carbon atom is sp
2
hybridized and forms pi bond.
(b) In diamond, carbon atom is sp
3
hybridized and has tetrahedral geometry.
(c) In graphite, carbon atom is sp
2
hybridized.
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