Solution
3Ω and 2Ω are in series
R
1
=3+2=5Ω
R
2
=30Ω
6Ω and 4Ω are in series
R
3
=6+4=10Ω
R
1
, R
2
and R
3
are connected in parallel
R
1
=
R
1
1
+
R
2
1
+
R
3
1
=
5
1
+
30
1
+
10
1
=
30
10
R=3Ω