Show all your work clearly on the scratch paper) Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 5.00 m. A person is standing 12.0 m away from the wall, equidistant from the loudspeakers. When the person moves 1.00 m parallel to the wall, she experiences destructive interference for the first time. What is the frequency of the sound
Answer:
The speed of sound in air to be 343 m/s.
Given:
distance ‘d’ = 5 m
L = 12 m
It can be concluded that path difference must be equal to half of the wavelength when person is observing destructive interference’y’ at 1 m distance from the equidistant position
Since
λ/2 = yd/L
λ/2 = (1 x 5)/12
λ = 0.833m
Frequency of the sound is given by,
f = v / λ => 343 / 0.833
f=411.6 Hz