The radius of the earth’s very nearly circular orbit around the sun is 1.5×1011m.

By Rebecca
1 Min Read

The radius of the earth’s very nearly circular orbit around the sun is 1.50×10 11 m. What is the magnitude of the earth‘s velocity and centripetal acceleration as it travels around the sun?

Answer:

Describing a distance of 2πr2.314.1.5×10111=9.42×1011m9×1011m

Velocity will be:  v=timedistance=3×1079×1011=3×104sm

Centripetal acceleration will be ac=rv2=1.5×1011(3×104)2=6×10−3s2m

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