Marta is solving the equation S = 2πrh + 2πr2 for h. Which should be the result?
StartFraction S Over 2 pi r EndFraction equals h. – r = h
StartFraction S minus r Over 2 pi r EndFraction equals h. = h
S – S minus StartFraction r Over 2 pi EndFraction equals h. = h
S – S minus StartFraction 2 pi Over r EndFraction equals h. = h
Answer:
(S-2πr^2)/ 2πr = h
Step-by-step explanation:
S = 2πrh + 2πr^2
Subtract 2 pi r^2 from each side
S-2πr^2 = 2πrh + 2πr^2 -2πr^2
S-2πr^2 = 2πrh
Divide each side by 2 pi r
(S-2πr^2)/ 2πr = 2πrh/2πr
(S-2πr^2)/ 2πr = h