If 51×3 is a multiple of 9, where x is a digits, then what is the value of x?

By Rebecca
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If 51×3 is a multiple of 9, where x is a digits, then what is the value of x?

Answer:

We have the sum of the digits of 51×3

= 5 +1 + x + 3
= 9 + x

Since, 51×3 is divisible by 9.

∴ (9 + x) must be divisible by 9,

∴ ( 9 + x) must be equal to 0 or 9 or 18 or 27 or ….

But s is a digit, then

9 + x = 9 => x = 0

9 + x = 18 => x = 9

9 = 27 => x = 18, which is not possible

∴ The required value of x = 0 or 9.

 

51×3

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