An aircraft has a liftoff speed of 33 m/s. What minimum constant acceleration does this require if the aircraft is to be airborne after a take-off run of 240 m
Answer:
2.27 m/s²
Explanation:
Recall that one of the equations of motion can be expressed as
v² = u² + 2as
where
v = final velocity = takeoff speed = 33m/s
u = initial velocity = rest = 0 m/s
a = acceleration ( we are asked to find this)
s = distance traveled = length of takeoff run = 240m
substituting the known values into the equation above,
v² = u² + 2as
33² = 0² + 2a(240)
1089= 480a
a = 1089/480
a = 2.27 m/s²