A uniform disk with mass 40.0 kg

By Allen Kazadi

A uniform disk with mass 40.0 kg and radius 0.200 m is pivoted at its center about a horizontal, frictionless axle that is stationary. The disk is initially at rest, and then a constant force 퐹=30.0푁is applied tangent to the rim of the disk.a) What is the magnitude 푣of the tangential velocity of a point on the rim of the disk after the disk has turned through 0.200 revolution?b) What is the magnitude 푎of the resultant acceleration of that point in part a?

Answer:

The magnitude of the tangential velocity is v= 0.868 m/s

The magnitude of the resultant acceleration at that point is a = 4.057 m/s^2

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