A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water is 19 degress. What is the distance between the boat and the shark?
Answer:
81.3 feet
Step-by-step explanation:
A shark is swimming 28 feet below sea level. If the angle of depression from a boat on the water is 19 degrees What is the distance between the boat and the shark?
We solve the above question using Trigonometric function of Tangent
tan θ = Opposite/Adjacent
θ = Angle of depression = 19°
Distance between the boat and the shark = Adjacent = ? = x
Opposite = 28 feet
Hence:
tan 19 = 28/x
Cross Multiply
tan 19 × x = 28
x = 28/tan 19
x = 81.317904575 feet
Approximately = 81.3 feet
The distance between the boat and the shark is 81.3 feet