A machine gun fires a bullet of mass 40g with a velocity1200ms−1. The man holding it can exert a maximum force of 144N on the gun. How many bullets can he fire per second at the most?
Solution: Change in momentum for each bullet fired is =401000×1200=48N If a bullet fired exerts a force of 48N on man’s hand so ρ man can exert a maximum force of 144N, number of bullets that can be fired =144/48=3 bullets.
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